Leetcode
1768. Merge Strings Alternately

1768. Merge Strings Alternately

Description

You are given two strings word1 and word2. Merge the strings by adding letters in alternating order, starting with word1. If a string is longer than the other, append the additional letters onto the end of the merged string.

Return the merged string.

Example 1

  Input: word1 = "abc", word2 = "pqr"
  Output: "apbqcr"
  Explanation: The merged string will be merged as so:
  word1:  a   b   c
  word2:    p   q   r
  merged: a p b q c r

Example 2

  Input: word1 = "ab", word2 = "pqrs"
  Output: "apbqrs"
  Explanation: Notice that as word2 is longer, "rs" is appended to the end.
  word1:  a   b 
  word2:    p   q   r   s
  merged: a p b q   r   s

Example 3

  Input: word1 = "abcd", word2 = "pq"
  Output: "apbqcd"
  Explanation: Notice that as word1 is longer, "cd" is appended to the end.
  word1:  a   b   c   d
  word2:    p   q 
  merged: a p b q c   d

Constraints

  • 1 <= word1.length, word2.length <= 100
  • word1 and word2 consist of lowercase English letters.

My Solution

 
/**
 * @param {string} word1
 * @param {string} word2
 * @return {string}
 */
var mergeAlternately = function(word1, word2) {
  let result = '';
  let i;
 
  // Loop through the length of the shortest word
  for (i = 0; i < word1.length && i < word2.length; i++) {
    result += word1[i] + word2[i];
  }
 
  // If there are any letters left in either word, add them to the result
  if (i < word1.length) {
    result += word1.slice(i);
  } else if (i < word2.length) {
    result += word2.slice(i);
  }
 
  return result;
}